Question

Q 32.35: The isotope 235U decays by alpha emission with a half-life of 7.0 x 108 y. It also decays (rarely) by spontaneous fission, and if the alpha decay did not occur, its half-life due to spontaneous fission alone would be 3.0 x 1017 y. At what rate do spontaneous fission decays occur in 1.0 g of 235U

Answer 1

rate of fission =5.89*10^3 1\Year

Step-by-step explanation:

we know that

rate of fission is given as
`rate of fission = (0.69)/((T_(1/2))_(fission)) *( Mass* Avogardo\ number)/(Molar\ mass)`

`(T_(1/2))_(fission) = 3*10^(17) y`

mass = 1.0 g

avogardo number = 6.02*10^23

molar mass of isotopes 235U =235

Putting all value to get rate of emission

rate of fission
`= (0.69)/(3*10^(17)) *(1.0*6.02*10^(23))/(235)`

rate of fission =5.89*10^3 1\Year