Question

Helppppp PLEASEEEEE!!!!

Answer 1

Hi!!

I’m going to attach an image with the work. I just want to explain to you how to do these types of problems.

When you first start trying to do Algebra it can be really hard and scary. I kinda just wanted to wash your worries about it and answer some questions that you may have leave a comment if you have questions.

What you were doing in these problems was trying to get a certain letter alone. Trying to get t by itself to see what it equals. “But how do I do that??” Allow me to explain!!

You need to do the inverse operations. Sound familiar? It basically means to do the very opposite of something.

The inverse of addition is subtraction.
The inverse of multiplication is division.
The inverse of subtraction is addition.
The inverse of division is multiplication.

Let’s say you had xb=c and you wanted to solve for x. What would you do?

Well, we can see that we need to divide. But wait a second...we need to get x alone! What do we do?!

Well, I would rewrite the equation to be bx=c. Yes, you are allowed to do this because of the Commutative Property of Multiplication.

Commutative property: When two numbers are multiplied together, the product is the same regardless of the order of the multiplicands. For example 4 * 2 = 2 * 4 (basically, this means you are allowed to swip swap the numbers, or in this case, letters.)

Now we are going to divide! bx=a
bx/b=a/b
x=a/b

“Huh? Why’d you divide a by b?”

Well, I did that because of this magical, Golden Algebra Rule: what you do to one side MUST be done to the other!!

I hope you found this helpful! If you have any questions feel free to ask me! Also, DO NOT BE AFRAID TO ASK YOU TEACHER FOR HELP!! They may seem a bit scary, but they’re there to help you! Don’t be shy

Answer 2

5)x=u+k

6) x=g-c

7)a=k/u

8)x=g/c

Explanation:

5) u=x-k

we sum by k both sides of the equations and we have:

u+k=x-k+k

x=u+k

6) g=c+x

we subtract by c both sides of the equations and we have:

g-c=c+x-c

x=g-c

7)u=k/a

we multiply by a both sides of the equations and we have:

u*a=k*a/a

u*a=k

we divide by u both sides of the equations and we have:

(u*a)/u=k/u

a=k/u

8)g=xc

we divide by c both sides of the equations and we have:

g/c=xc/c

x=g/c