Explanation:
The first one (f×g)(x) is asking you what is f of x times g of x. This means you multiply the function. You can multiply by the first term (5x) then the second (3) and combine like terms.
![{15x}^(2) (5x) = {75x}^(3) \\ 19x(5x) = 95 {x}^(2) \\ 6(5x) = 30x](https://img.qammunity.org/2020/formulas/mathematics/high-school/dpgsdsp8428y6q0khprgyodgxx8mvg630v.png)
![{15x}^(2) (3) = 45 {x}^(2) \\ 19x(3) = 57x \\ 6(3) = 18](https://img.qammunity.org/2020/formulas/mathematics/high-school/yez95ufnxhvn76l5sf1woiwoaabie3rkpb.png)
Combine like terms
![{75x}^(3) + {95x}^(2) + {45x}^(2) + 30x + 57x \\ + 18 = \\ {75x}^(3) + {140x}^(2) + 87x + 18](https://img.qammunity.org/2020/formulas/mathematics/high-school/ozwaqa4dr9h4xmy9cuqaymohk5m6k0cmbz.png)
The second one asks you to divide.
Factor out f(x):
![{15x}^(2) + 19x + 6](https://img.qammunity.org/2020/formulas/mathematics/high-school/3mmz5gfpfhv5auecu57zxsn31d0trrcdqy.png)
From dividing f(x) /g(x)
![\frac{ {15x}^(2) + 19x + 6 }{5x + 3}](https://img.qammunity.org/2020/formulas/mathematics/high-school/3o6fpxqvrz4l7dbe3x0hnubdem5gthwilb.png)
To
![((5x + 3)(3x + 2))/(5x + 3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4tjhnes4x5b4hoeltsvmtbchxrhvojwqqx.png)
Cancel like terms since (5x+3) is on top and bottom of fraction.
You get 3x+2