Answer:
a. 0.504
b. 0.496
Explanation:
Given,
There are 4 digit in a number,
In which the possible number in first position = 3 (i.e. 6, 7, 8 )
If the repetition of digit is not allowed,
The possible number in second position = 9
In third position = 8
And, in fourth position = 7
Thus, the possible ways of arranging a number in which each contains different digit
= 3 × 9 × 8 × 7
= 1512,
While, the total possible ways of arranging 4 numbers = 3 × 10 × 10 × 10 = 3000
a. Hence, the probability that a randomly-chosen phone number contains all different digits =
![(1512)/(3000)](https://img.qammunity.org/2020/formulas/mathematics/college/pzcqmef66h97wlk9b1k44u4v7divhtn5vm.png)
![=0.504](https://img.qammunity.org/2020/formulas/mathematics/college/zuvwpkn6o0p7wiss2dp3donlfw0r2wpe8s.png)
b. The probability that a randomly-chosen phone number contains at least one repeated digit = 1 - the probability that a randomly-chosen phone number contains all different digits
= 1 - 0.504
= 0.496