Answer:
![V=(448\pi)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v09a5a9xf2jnhxmdodptronpx9m9zfneo9.png)
Explanation:
We are given that curves y=
is rotated about x=4 .
Given that y=0 and x=2
We have to find the volume V generated by rotating the region bounded by the curves with the help of method of cylindrical shells.
First we find the intersection point
Substitute y=0 then we get
0=
![3x^4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t185zhj3537jv5rkvae7xpmg6t8cweennd.png)
x=0
Hence, x changes from 0 to 2.
Radius =4-x
Height of cylinder =y=
![3x^4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t185zhj3537jv5rkvae7xpmg6t8cweennd.png)
Surface area of cylinder =
![2\pi r h](https://img.qammunity.org/2020/formulas/mathematics/high-school/5ze04hh8zlmph3wkb9hat0besh398vja3c.png)
Volume V generated by the rotating curves
=
![2\pi\int_(0)^(2) (4-x)(3x^4)dx](https://img.qammunity.org/2020/formulas/mathematics/high-school/ou11883nozlbhcigitm6biuihdgvk89vah.png)
V=
![2\pi\int_(0)^(2)(12x^4-3x^5)dx](https://img.qammunity.org/2020/formulas/mathematics/high-school/57119i0cch4we1tsyihoja5tolkeyd9ybi.png)
V=
![2\pi[(12x^5)/(5)-(x^6)/(2)]^2_0](https://img.qammunity.org/2020/formulas/mathematics/high-school/h4fec4yze4xfktre110fwdxpj7gih945vq.png)
V=
![2\pi[(384)/(5)-32]](https://img.qammunity.org/2020/formulas/mathematics/high-school/3t04t6765wwmoeljyt2igti8ylrcokx53h.png)
V=
![2\pi(384-160)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/mxidaovfo64lk5yk2dpkmimtnj2xydpgfs.png)
![V=(448\pi)/(5)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v09a5a9xf2jnhxmdodptronpx9m9zfneo9.png)
Hence, the volume V generated by rotating the region by the given curves about x =4=
.