Answer:
the maximum mass suspended to the styrofoam sphere is m = 113.1 kg
Step-by-step explanation:
The weight due to suspended mass is counterbalanced by the buoyancy force on the sphere
So here we will say
![F_b = mg](https://img.qammunity.org/2020/formulas/physics/high-school/nvu4muefa5ez2lk415e2h0mbha1i09r8w0.png)
as we know that the maximum buoyancy force that will act on the styrofoam sphere is given as
![F_b = \rho V g](https://img.qammunity.org/2020/formulas/physics/college/zehzt1wofu0wfymtisvs9a4vcfzlevtk3m.png)
![F_b = (1000)((4)/(3)\pi r^3)g](https://img.qammunity.org/2020/formulas/physics/high-school/3k5dp05rupztv2dogsriddgsid46srpaa8.png)
![F_b = (1000)((4)/(3)\pi(0.30)^3)(9.81)](https://img.qammunity.org/2020/formulas/physics/high-school/kjzjd3d29yaazbmtghlfjv2aqxi43fopqs.png)
![F_b = 113.1 * 9.81](https://img.qammunity.org/2020/formulas/physics/high-school/nevks65uw3ajtsrmu6ywksmq5btyhc8x2c.png)
now from above equation we have
![113.1 * 9.81 = m* 9.81](https://img.qammunity.org/2020/formulas/physics/high-school/g4v6h21u8o9yipafl4ppgvj5oejxe7p6kr.png)
![m = 113.1 kg](https://img.qammunity.org/2020/formulas/physics/high-school/i7d5pyruq7byfhyy42cniziw4tq0i10ulg.png)
so the maximum mass suspended to the styrofoam sphere is m = 113.1 kg