Answer:
The fraction is
![(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/e902xdvhskq5go8rzqwzc0u5ermj5vc0m5.png)
Explanation:
* Lets explain how to solve the problem
- The fraction m/n has m as a numerator and n as a denominator
- To compare between fractions we must to put all of them with
same denominator
- We can make that by find the lowest common multiple (L.C.M) of
the all denominators
- Ex: The L.C.M of the denominators of these fraction
is 12 because 12 is the first
common multiple of 2 , 4 , 6
- The fractions will be change:
#
⇒ we multiplied up and down by 6
to make the denominator = 12
#
⇒ we multiplied up and down by 3
to make the denominator = 12
#
⇒ we multiplied up and down by 2
to make the denominator = 12
- The fractions will be
![(6)/(12),(9)/(12),(10)/(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zv3l7uefux8eubgt39yah678z2qpsko8nm.png)
* Lets solve the problem
- To chose a fraction between
, we must
find The L.C.M for the denominators 8 and 5
∵ The least common multiple of 8 and 5 is 40
∴ The fraction
⇒ we multiplied up
and down by 5 to make the denominator = 40
∴ The fraction
⇒ we multiplied up
and down by 8 to make the denominator = 40
- Lets find any fraction between
and
![(24)/(40)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/txrdulaws7s6ea1obluxx33uo8uax92ke7.png)
∵ The fraction
is between the fractions
and
∴
![(35)/(40)>(30)/(40)>(24)/(40)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/q153v5pwsmcpvu3cegacmmfnhz41pl2tjc.png)
- Lets reduce the fraction to its simplest form
∵ The simplest form of
is
![(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/e902xdvhskq5go8rzqwzc0u5ermj5vc0m5.png)
by dividing up and down by 10
∴
![(7)/(8)>(3)/(4)>(3)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e8ihi3nx3fn03my7c6evvyqdge7sfp4hzp.png)
* The fraction is
![(3)/(4)](https://img.qammunity.org/2020/formulas/mathematics/college/e902xdvhskq5go8rzqwzc0u5ermj5vc0m5.png)