Question

A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross section of the wire

Answer 1

Answer: 162500000

Step-by-step explanation:

given data:

wire diameter = 1.8mm

wire length = 15cm

current = 260mA.

electron charge e =
`1.6*10^(-19) C`

Solution:

`I = (q)/(t)`

where:

`I = current\\\\q = charge\\\\t = time \\\\q=It\\\\q= 260mt`

`q=ne\\\\n = (q)/(e) \\\\n= (260*10^(-3) t)/(1.6*10^(-19) ) \\\\n= 162500000t\\\\(n)/(t) = 162500000`

number of electrons per seconds would be 162500000