Question

What volume would a 0.871 gram sample of air occupy if the density of air is 1.29 g/L?

Answer 1

Answer : The volume of the sample of air will be 0.675 L

Explanation :

Density : It is defined as the mass of a substance contained per unit volume.

Formula used :

`Density=(Mass)/(Volume)`

Given:

Mass of sample of air = 0.871 g

Density of air = 1.29 g/L

By using formula, we get:

`1.29g/L=(0.871g)/(Volume)`

`Volume=0.675L`

Thus, the volume of the sample of air will be 0.675 L

Answer 2

`\boxed{\text{675 mL}}`

Step-by-step explanation:

`V = \text{0.871 g} * \frac{\text{1 L}}{\text{1.29 g}} = \text{0.675 L} = \textbf{675 mL}\\\\\text{The volume of air is } \boxed{\textbf{675 mL}}`