Answer: Option A
![P(A|B)=(3)/(5)=0.6](https://img.qammunity.org/2020/formulas/mathematics/high-school/gt8n8v3c8gnpx5hj9nrrlgtlaw3uy7qecp.png)
Explanation:
By Definition the probability of A given B is:
![P(A|B)=(P(A\ and\ B))/(P(B))=(A\ and\ B)/(B)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5mwhvljh2db3v15g5tp6r6jwlk2f3invpi.png)
Note that the number of students playing basketball is 6
The number of students playing soccer is 5
The number of students who play both sports is 3
Therefore we have that:
![P(A|B)=(3)/(5)=0.6](https://img.qammunity.org/2020/formulas/mathematics/high-school/gt8n8v3c8gnpx5hj9nrrlgtlaw3uy7qecp.png)
The answer is the option A