Question

What is Keq for the reaction 2HCl(9) = H2(g) + Cl2(9)?

Answer 1

Answer: The expression of
`K_(eq)` is written below.

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
`K_(eq)`

For a general chemical reaction:

`aA+bB\rightarrow cC+dD`

The expression for
`K_(eq)` is written as:

`K_(eq)=([C]^c[D]^d)/([A]^a[B]^b)`

Concentration of solid and liquid substances in a chemical reaction is taken to be 1.

For the given chemical equation:

`2HCl(g)\rightleftharpoons H_2(g)+Cl_2(g)`

The expression of
`K_(eq)` for the above equation follows:

`K_(eq)=([Cl_2]* [H_2])/([HCl]^2)`

Hence, the expression of
`K_(eq)` is written above.

Answer 2

Keq = ( [ H2(g) ] * [ Cl2(g) ] ) / [ HCl(g) ]²

Step-by-step explanation:

from de la reaction:

• 2HCl(g) ↔ H2(g) + Cl2(g)

⇒ Keq = ( [ H2(g) ] * [ CL2 ](g) ) / [ HCl(g) ]²