Question

How do you calculate log base 6 of 9 by using changing bases

Answer 1

1.2262943855309168262595...

Explanation:

You use the change of base formula:

`log_b(a) = (log_c(a))/(log_c(b))`

So in essence, you can take any base c and just divide by the log of the original base b.

A special base is e, which gives you the natural log ln.

So even ln 9 / ln 6 gives the same answer.