Question

a car is moving 18.2 starts to coast UP a frictionless 10.0 hill. How far does it roll before coming to a stop?

Answer 1

97.3 m/s

The up answer has the right answer for THEIR equation. but that is NOT helpful to you since you asked a different question. You asked for 18.2 not 18.3. so heres the right answer.

Answer 2

The car travels 98.4m before coming to the stop !

Step-by-step explanation:

First let "
`s`" be the distance up the plane.

Then, By conservation of energy.

`(1)/(2) m(18.3)^2 = mg`
`s`
`sin(10)`

`(18.3)^2 = 2g`
`s`
`sin(10)`

`s = ((18.3)^2)/(2gsin(10) )`

`= 98.39564526`

`= 98.4 m`