Question

The co-ordinate of point P is (x+3) and Q is (x-3). Then find d(P,Q). If coordinate of R is (x+2). Find d(Q,R).

Answer 1

d(P, Q) = 6

d(Q, R) = 5

Explanation:

The formula of a distance between two points A(a) and B(b):

d = |b - a|

We have P(x + 3), Q(x- 3), R(x + 2).

Substitute:

d(P, Q) = |(x - 3) - (x + 3)| = |x - 3 - x - 3| = |-6| = 6

d(Q, R) = |(x + 2) - (x - 3)| = |x + 2 - x - (-3)| = |2 + 3| = |5| = 5