Question

A local park is building a sand volleyball court 40 feet long and 15 feet wide. They are paying $3000 to have the sand put into the court. How much does the court cost per square foot of sand?

Answer 1

$5 per square feet.

Explanation:

A local park is building a stand volleyball court that is 40 feet long and 15 feet wide.

Area of the volleyball court = length × width

= 40 × 15

= 600 feet²

They are paying $3,000 to have the stand put into the court.

The cost per square foot of stand =
`(3000)/(600)`

= 5 dollar per square

The cost is $5 per square feet of stand.

Answer 2

The court cost $5 per square foot of sand

Explanation:

step 1

Find the area of the volleyball court

The area of the rectangular court is equal to

`A=LW`

we have

`L=40\ ft`

`W=15\ ft`

substitute

`A=(40)(15)=600\ ft^(2)`

step 2

Divide the total cost to have the sand put into the court by the area of the court

so

`(3,000)/(600)(\$)/(ft^(2))=5(\$)/(ft^(2))`

therefore

The court cost $5 per square foot of sand