Question

If sin tita = cos tita find tita between 0° and 30°​

Answer 1

The equality sin tita equals cos tita occurs at 45°, which is not between 0° and 30°, so there is no angle within the specified range that meets the condition.

Step-by-step explanation:

When sin tita is equal to cos tita, we are looking for an angle where the values of sine and cosine are the same.

Since the sine and cosine functions are complements of each other within the first 90 degrees (0° to 90°), this equality happens when the angles add up to 90 degrees.

Therefore, if sin tita = cos tita, then tita + tita = 90°, leading to 2 * tita = 90° and thus tita = 45°.

However, the student is looking for an angle between 0° and 30°.

Since there is no angle within that range where sine and cosine are equal, the initial condition cannot be met within the specified range.

Answer 2

there is no solution for (0, 30°)

Step-by-step explanation:

six(x) = cos(x)

sin(x) - cos(x) = 0

(sin(x) - cos(x))^2 = 0

sin(t)^2 + cos(x)^2 - 2sin(x)cos(x) = 0

1 - sin(2x) = 0

sin(2x) = 1

2x = π/2 + 2πk -> k - any integer number

x = π/4 + πk

the smallest positive solution is π/4 = 45°. That means for range (0, 30°)

there is no solution