Answer:
5.96 minutes
Step-by-step explanation:
Two RSM students are standing 20ft
Speed of one student = 300 ft/min
Speed of other student = 200 ft/m
Time they run till they reach a distance of 3000 ft = x
Distance = Speed × time
![300x+200x+20=3000\\\Rightarrow 500x+20=3000\\\Rightarrow 500x=3000-20\\\Rightarrow 500x=2980\\\Rightarrow x=(2980)/(500)\\\Rightarrow x=5.96\ minutes](https://img.qammunity.org/2020/formulas/physics/high-school/mqx1a6qqdkdnl88daf47mlt0lwywwiggu2.png)
∴ Time taken to reach a gap of 3000 ft is 5.96 minutes.