Question

Please help me with this question

Answer 1

-29/20

Explanation:

`\csc x=(1)/(\sin x)\\\\\sin(-x)=-\sin x\to\csc(-x)=-\csc x\\\\\sin\theta=(20)/(29)\to\csc(-\theta)=-\csc\theta=-(1)/((20)/(29))=-(29)/(20)`

`0^o<\theta<90^o\to\text{I Quadrant}\to\sin\theta>0\\\\-\theta\to\text{IV Quadrant}\to\sin\theta<0`

Answer 2

csc=1/sin
instead of the angle sign I'll use x
AKA the reciprocal of sin
If sin x=20/29,
csc -x=1/sin -x
sin -x = -20/29
csc -x = -29/20