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Mg(s)+Cr3+(aq) → Mg2+(aq)+Cr(s) Express your answer as a chemical equation. Identify all of the phases in your answer. Express your answer as a chemical equation. Identify all of the phases in your answer. Express your answer as a chemical equation. Identify all of the phases in your answer.

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Step-by-step explanation:

As the given chemical reaction equation is as follows.


Mg(s) + Cr^(3+)(aq) \rightarrow Mg^(2+)(aq) + Cr(s)

Hence, the oxidation and reduction-half reactions will be as follows.

Oxidation-half reaction:
Mg(s) \rightarrow Mg^(2+) + 2e^(-) .....(1)

Reduction-half reaction:
Cr^(3+)(aq) + 3e^(-) \rightarrow Cr(s) ....(2)

So, in order to balance the oxidation and reduction half reactions, we multiply equation (1) by 3 and multiply equation (2) by 2.

Therefore, the balanced oxidation and reduction half reactions will be as follows.

Oxidation-half reaction:
3Mg(s) \rightarrow 3Mg^(2+) + 6e^(-)

Reduction-half reaction:
2Cr^(3+)(aq) + 6e^(-) \rightarrow 2Cr(s)

Thus, we can conclude that the overall balanced reaction equation will be as follows:


3Mg(s) + 2Cr^(3+)(aq) \rightarrow 3Mg^(2+)(aq) + 2Cr(s)

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