Question

At a point in the pattern where the phase difference between the waves from the two slits is 58.0 ∘, what is the intensity? Give your answer as a fraction of I0.

Answer 1

The intensity is 0.559.

Step-by-step explanation:

Given that,

Angle = 58.0°

The intensity at the peak of the central maximum is I₀

We need to calculate the intensity

Using formula of intensity

`I=I_(0)\cos^2((\phi)/(2))`

Where, I = intensity

`I_(0)`=maximum intensity

Put the value into the formula

`(I)/(I_(0))=\cos^(2)((58.0)/(2))`

`(I)/(I_(0))=0.559`

Hence, The intensity is 0.559.