Answer:
Part a) The volume of the air is
![V=7,794.78\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nwu7rl8rmevt1sk2yoqrqk4dd68a9srqdn.png)
Part b) The volume of the plastic is
![V=386.45\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dycux3wjtazag8fp8sm10q2waja16w8y8i.png)
Explanation:
we know that
The volume of the sphere is equal to
![V=(4)/(3)\pi r^(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/904v6t92j764tuemw89ou00p3u81fhmqpa.png)
step 1
Find the volume of the complete ball (air +plastic)
we have
------> the radius is half the diameter
substitute
![V=(4)/(3)\pi (12.5)^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o99rspzi9xccy3frsrfdyujha0m3wjug1r.png)
![V=8,181.23\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yai18nyu1opafys9n4jg17r0g2fuev9z90.png)
step 2
Find the volume of the air
we have that
The plastic is 2 mm thick
Convert to cm
2 mm=2/10=0.2 cm
so
The radius of the interior of the ball is
![r=12.5-0.2=12.3\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u1bncsr6zxmy5k6n77ekof8m80ai769ycw.png)
substitute
![V=(4)/(3)\pi (12.3)^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8ocu948kkw0mb7ip7jjaaphjcwjazw0fjv.png)
-----> this is the volume of the air (interior of the ball)
step 3
Find the volume of the plastic
we know that
The volume of the plastic is equal to the volume of the complete ball minus the volume of the air
so
![8,181.23\ cm^(3)-7,794.78\ cm^(3)=386.45\ cm^(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aubz02tc4gipvhwi02oypaafy42udkhdpg.png)