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Find parametric equations for the tangent line to the curve of intersection of the paraboloid z = x2 + y2 and the ellipsoid 3x2 + 2y2 + 4z2 = 21 at the point (−1, 1, 2). (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of t.)

1 Answer

5 votes

Answer:


x=-1-18 t,y=1+19 t,z=2-2 t

Explanation:

We are given that

Equation of paraboloid


z=x^2+y^2


z-x^2-y^2=0

And equation of the ellipsoid


3x^2+2y^2+4z^2-21=0

We have to find the parametric equation for tangent line to the curve of the intersection of the paraboloid and ellipsoid at point (-1,1,2).

We have to find the normal at point (-1,1,2)


N_1=-2x\hat{i}-2y\hat{j}+\hat{k}

Normal at point (-1,1,2)


N_1=<2,-2,1>


N_2=6x\hat{i}+4y\hat{j}+8z\hat{k}

Normal at point (-1,1,2)


N_2=<-6,4,16>

We rescale and set
N_2=<-3,2,8>

The tangent vector to the curve of intersection is given by


N_1\time N_2=
\begin{vmatrix}\hat{i}&amp;\hat{j}&amp;\hat{k}\\2&amp;-2&amp;1\\-3&amp;2&amp;8\end{vmatrix}


N_1* N_2=<-18,19,-2>

Hence, the tangent line is given by


x=-1-18 t,y=1+19 t,z=2-2 t

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