Answer: 456
Step-by-step explanation:
Given : Significance level :
![\alpha= 1-0.98=0.02](https://img.qammunity.org/2020/formulas/computers-and-technology/college/671d64wnvpz6rb1pht424l0spzq0ejnrwx.png)
Critical value :
![z_(\alpha/2)=2.33](https://img.qammunity.org/2020/formulas/mathematics/college/57cf9sg1nhketuvdumn3ws065pqjdm3tjj.png)
Margin of error :
![E=\pm0.05](https://img.qammunity.org/2020/formulas/computers-and-technology/college/5cye61u3qcp6ta6b42jgm25qjph55avrnc.png)
The prior proportion of employee e-mail is not business related:
![p=0.30](https://img.qammunity.org/2020/formulas/computers-and-technology/college/s2nc1a4dq1p0oua9c574lafpf5pveo48hb.png)
The formula to find the sample size is given by :-
![n=(p(1-p))((z_(\alpha/2))/(E))^2](https://img.qammunity.org/2020/formulas/computers-and-technology/college/3hrifnqpwcrbzh7hru7i22wp0n4id02idt.png)
i.e.
![n=(0.3(0.7))(((2.33))/(0.05))^2=456.0276\approx456](https://img.qammunity.org/2020/formulas/computers-and-technology/college/8cvobcdojcer7wglwbjkbvthqyjj5ia5sl.png)
Hence, Elwin should sample 456 e-mail messages.