Answer:
![7506.1035J](https://img.qammunity.org/2020/formulas/physics/middle-school/yt6m2akvxdilwf3brht739518kay82kkhc.png)
Step-by-step explanation:
We can use the relation
Q =mcΔθ
to find the energy required to heat the iron nail, where Q is the heat energy required, m is the mass of the nail and Δθ is change in temperature and c is heat capacity of the iron nail.
Also, from the question,
![m= 25.5g](https://img.qammunity.org/2020/formulas/physics/middle-school/fxe71evfuu4lp6uhk3o2a6bqlb8obvbf1d.png)
c = 0.4494J/g°C
Δθ=720 - 65 = 655°C
By substitution
![Q =25.5 * 0.4494 * 655](https://img.qammunity.org/2020/formulas/physics/middle-school/bfipxev1tswenm5z66uxuz3zhtp8rvwl3j.png)
![Q=7506.1035J](https://img.qammunity.org/2020/formulas/physics/middle-school/ewm5vnpgwh0p08uxazvwevmkt88x64n5sn.png)
Hence the energy required to heat the iron nail is 7506.1035J