Question

A scalloped hammerhead shark swims at a steady speed of 1.7 m/s with its 89-cm-wide head perpendicular to the earth's 52 μT magnetic field. You may want to review (Pages 806 - 809) . Part A What is the magnitude of the emf induced between the two sides of the shark's head

Answer 1

The magnitude of the emf induced between the two sides of the shark's head is
`7.87*10^(-5)\ V`

Step-by-step explanation:

Given that,

Steady speed = 1.7 m/s

Wide = 89 cm

Magnetic field = 52\mu T

We need to calculate the emf induced

Using formula of induced emf

`\epsilon = Blv`

Where, B = magnetic filed

l = length

v = speed

`\theta=90^(\circ)`

`\sin90=1`

Put the value into the formula

`\epsilon=52*10^(-6)*89*10^(-2)*1.7`

`\epsilon=7.87*10^(-5)\ V`

Hence, The magnitude of the emf induced between the two sides of the shark's head is
`7.87*10^(-5)\ V`