Question

An archer hits the center of the target (the bullseye) 70 percent of the time. However, she is a streak shooter, and if she hits the center on one shot, her probability of hitting it on the shot immediately following is 0.85. Written in probability notation: P(A) = P(B) = P (hitting the center on one shot) = 0.70 P(B|A) = P (hitting the center on a second shot, given that she hit it on the first) = 0.85 Calculate the probability that she will hit the center of the target on two consecutive shots.

Answer 1

0.595

Explanation:

We are given that An archer hits centre of the target

We have to calculate the probability that she will hit the centre of the target on two consecutive shots.

P(A)=P(B)=0.70

P(B/A)=0.85

We know tha formula

`P(B/A)=(P(A\cap B))/(P(A))`

Substitute the value then we get

`P(A\cap B)=P(B/A)\cdot P(A)=0.85* 0.70=0.595`

Hence, the probability that she will hit the centre of the target on two consecutive shots=0.595