Question

A ballistic pendulum consists of a 3.60 kg wooden block on the end of a long string. From the pivot point to the center‐of‐mass of the block is a distance of 2.80 m. With the pendulum hanging straight down, a rifle bullet of 28.0 g mass moving with a speed of 210 m/s embeds itself into the wood. To what maximum angle does the pendulum (with embedded bullet) swing upward?

Answer 1

17.799°

Step-by-step explanation:

When the bullet hits the block at that time the momentum is conserved

So, initial momentum = final momentum

`P_i=P_f`

So
`28* 10^(-3)* 210=(3.6+0.028)v_f`

`v_f=1.6207\ m/sec`

Now energy is also conserved

So
`(1)/(2)* (3.6+0.028)* 1.6207^2=(3.6+0.028)* 9.81* 2.8(1-cos\Theta )`

`cos\Theta =0.8521So\ \Theta =17.799^(\circ)`