Question

A block of mass 0.253 kg is placed on top of a light, vertical spring of force constant 4 825 N/m and pushed downward so that the spring is compressed by 0.097 m. After the block is released from rest, it travels upward and then leaves the spring. To what maximum height above the point of release does it rise? (Round your answer to two decimal places.)

Answer 1

Step-by-step explanation:

It is given that,

Mass of the block, m = 0.253 kg

Force constant, k = 4825 N/m

Compression in the spring, x = 0.097 m

After the block is released from rest, it travels upward and then leaves the spring. Using the conservation of energy as :

`(1)/(2)kx^2=mgh`

`h=(kx^2)/(2mg)`

`h=(4825* (0.097)^2)/(2* 0.253 * 9.8)`

h = 9.15 m

So, the block will go to the maximum height of 9.15 meters. Hence, this is the required solution.