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A capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280-mH inductor. Calculate: (a) the oscillation frequency of the circuit; (b) the energy stored in the capacitor at time (the moment of connection with the inductor);

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Frequency = 1 / (2π√LC)

Frequency = 1 / (2π · 2.8 x 10⁻⁴ · C)

Frequency = 1 / (1.759 x 10⁻³ · C)

Frequency = (568.4 / C) Hz.

Energy stored in a capacitor = 1/2 C V²

Energy = 1/2 C · 2.25 x 10⁴

Energy = (11,250 · C) Joules

Neither of the answers can be completely specified without knowing the value of the capacitor.

User Manoj Acharya
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