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In AJKL, Solve for x.
270
к
34
D
-

In AJKL, Solve for x. 270 к 34 D --example-1

1 Answer

6 votes

Answer:

74.89

Explanation:

In ∆JKL,

sin 27°=KL/JL

sin27°=34/x

x=34/sin27°

x=34/0.45

x=74.89

User Robert Rouhani
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