Question

Use the Law of Logarithm to expand the expression. ln(y √x/z (I know the answer is 2ln(y)+ln(x)-ln(z) all over 2, but I need the steps to get there)

Answer 1

`in (y\sqrt{(x)/(y)}) =(1)/(2) in(x)-(1)/(2) in(z) +in(y)`

Explanation:

From the question we are told that the expression
`ln(y √x/z`

`in (y\sqrt{(x)/(y)})`

`in(y)+in(y\sqrt{(x)/(y)})`

`in(xy)=in(x)+in(y)`

`in(xy)=in(x)/(z) ^1^/^2 +in(y)`

`in(xy)=(1)/(2) in((x)/(z)) +in(y)`

`in(xy)=(1)/(2) in(x)-in(z) +in(y)`

`in(xy)=(1)/(2) in(x)-(1)/(2) in(z) +in(y)`

Mathematically

`in (y\sqrt{(x)/(y)}) =(1)/(2) in(x)-(1)/(2) in(z) +in(y)`