121k views
4 votes
What are the solutions to the equation X^2+2x+2=0

User Poy Chang
by
7.5k points

1 Answer

0 votes

Answer:

x=0 and x = -2

Explanation:

So we know that a^2 + 2ab + b^2 = (a+b)^2 so, in this situation, we got:

x^2 + 2x + 2 = 0

x^2 + 2x + (1/2*2)^2 +1 = 0

x^2 + 2x + 1^2 + 1 = 0

(x+1)^2 + 1 = 0

(x+1)^2 + 1^2 = 0

We also learn that a^2 + b^2 = (a+b) * (a-b), so in this case:

(x+1)^2 + 1^2 = 0

(x+1+1) * (x+1-1) = 0

(x+2) * (x+0) = 0

x(x+2) = 0

So, there would be 2 result for x now:

x = 0 and x+2 =0

x=0 and x = -2

Hope this help you :3

User Alfons
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories