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What is the value of h(-2) if h(x)=4x^2-x+9?

What is the value of h(-2) if h(x)=4x^2-x+9?-example-1
User Llanilek
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2 Answers

5 votes

Answer:

16x² + 2x + 9

Explanation:

To evaluate h(- 2x) , substitute x = - 2x into h(x), that is

h(- 2x)

= 4(- 2x)² - (- 2x) + 9

= 4(4x²) + 2x + 9

= 16x² + 2x + 9

User Czw
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4.5k points
6 votes
h(-2) = 4(-2x)^2-(-2x)+ 9
= 4(4x^2)+2x+9 = 16x^2 + 2x + 9
User Florian Mutel
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