Question

If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step

Answer 1

Step-by-step explanation:

`v_f^2 = v_i^2-2a(x_f-x_i)`

Subtract both sides by
`v_i^2`:

`- v_i^2+v_f^2 = -2a(x_f-x_i)`

Divide both sides by -2*a:

`(v_i^2 - v_f^2)/(2a) =x_f-x_i`

Add both sides by
`x_i`:

`x_i+(v_i^2 - v_f^2)/(2a) =x_f`

Subtract both sides by
`(v_i^2 - v_f^2)/(2a)`:

`x_i=x_f-(v_i^2 - v_f^2)/(2a)`