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If dy/dx = x^2 + 4 what is the value of y

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Answer:

y = (1/3)x^3 +4x + c . . . . . for some constant c

Explanation:

The anti-derivative of x^n is (x^(n+1))/(n+1). Applying this rule to each of the terms in dy/dx, we get ...

y = (1/3)x^3 + 4x

There may be an added constant as well, conventionally represented by "c".

y = (1/3)x^3 +4x +c

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