Answer:
837.02 ohms
Step-by-step explanation:
Step one:
Given data
Frequency= 60Hz
L1= 0.75H
L2= 1.47H
When inductors are connected in series, the total inductance is the sum of the individual inductance
Step two:
Inductor 1
![Xl1= 2\pi fL\\\\Xl1= 2*3.142*60*0.75\\\\Xl1= 282.78 ohms](https://img.qammunity.org/2022/formulas/chemistry/college/bxbe5pdj78eashgwz84j3ny8r0kptokrlg.png)
Inductor 2
![Xl2= 2\pi fL\\\\Xl2= 2*3.142*60*1.47\\\\Xl2= 554.24 ohms](https://img.qammunity.org/2022/formulas/chemistry/college/wy40oyg8nqs5lm1j6w2rgygbd17wg0iwa8.png)
The total inductance is
=282.78+554.24
=837.02 ohms