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two negative integers are 8 units apart on the number line and have a product of 308. Which equation could be used to determine x, the smaller negative integer?

User Joepio
by
8.0k points

2 Answers

5 votes

Answer:

Integer are (-14) and (-22). The smallest integer is (-22).

Explanation:

Let the integer be (-x) and (-y)

(-y) - (-x) = 8 (x here is a smaller integer)

-x = b, -y = a

a - b = 8...(1)

(-a)(-b) = 308..(2)

Putting value of ab from (2) in (1):


a=(308)/(b)


(308)/(b)-b=8


b^2-8b-308


b=-14,22


b=-x


-14=-x (b=-14)

x = 14 (reject, integer asked are negative)


b=-x


22=-x (b=22)

x = -22


a=(308)/(b)=(308)/(22)=14


a=14=-y

y = -14

Integer are (-14) and (-22). The smallest integer is (-22).

User Myrtlecat
by
7.7k points
7 votes

Answer:


x = -22

Explanation:

The formula for calculating the distance between two integers x and y is:


| y-x | = d

Where d is the difference between the two numbers and x is the smallest integer

In this case we know that
d = 8 then:


| y-x | = 8

We also know that the product of both numbers is equal to 308.

This means that:


xy = 308

We know that
x <y and that
x <0 and
y <0

then the difference of
y-x will always be positive, for this reason we can eliminate the absolute value of the first equation and we have that:


y-x = 8

and


xy = 308

We substitute the first equation in the second equation:


x (x + 8) = 308

Now we solve for x:


x ^ 2 + 8x -308 = 0

To factor the equation, you must look for two numbers that, by multiplying them, you get as a result -308 and by adding these numbers you get as a result 8.

These numbers are 22 and -14

Then the equation is as follows:


(x + 22) (x-14) = 0

The solutions are:


x = -22, and
x = 14

As we know that
x <0 then we take the negative solution
x = -22

Finally we find the value of y.


y -(-22) = 8


y = -22 + 8


y = -14

User Nat Naydenova
by
8.3k points