Question

"A baseball player comes to bat 4 times in a game. The chance of a strike-out for this player is 30%. What is the probability that the player does not strike out for the entire game?

Answer 1

Answer: 0.2401

Explanation:

Given : A baseball player comes to bat 4 times in a game

The probability that a strike-out for this player= 0.30

The binomial probability distribution :-

`P(x)=^nC_xp^x(1-p)^(n-x)`, where P(X) is the probability of getting success in x trials, n is the total number of trials and p is the probability of success in each trial ( in decimal ).

Now, the probability that the player does not strike out for the entire game :-

`P(x)=^4C_0(0.3)^0(0.7)^(4)\\\\=(0.7)^(4)\\\\=0.2401`

Hence, the required probability = 0.2401