Step-by-step explanation:
The attached figure shows the whole description.
Fraction covered in south,
![x_1=(1)/(2)](https://img.qammunity.org/2020/formulas/physics/high-school/h9ckcidvpjq8xnegsybwwt59m3ylygtsf1.png)
Fraction covered in east,
![x_2=(3)/(4)](https://img.qammunity.org/2020/formulas/physics/high-school/shb1mngaz6r9ktxyq06zoupw47pcgxjv79.png)
Fraction covered in south,
![x_3=(1)/(2)](https://img.qammunity.org/2020/formulas/physics/high-school/n5wkra78kc5eotfz9lmafurs13uyerpgwh.png)
MNO is a right angle triangle.
![MO^2=MN^2+NO^2](https://img.qammunity.org/2020/formulas/physics/high-school/tqbzv7zumnrwbkn16tbh2w7uxaativ1os2.png)
![MO^2=(3/8)^2+(1/2)^2](https://img.qammunity.org/2020/formulas/physics/high-school/yi7jh2uchpcgbjdg22kediul5graaaz8rq.png)
![MO=0.62\ mile](https://img.qammunity.org/2020/formulas/physics/high-school/q9fmunsxf9hi26fghvo92wd7ojjubrr7pw.png)
So,
![AM=2* MO](https://img.qammunity.org/2020/formulas/physics/high-school/3tx1ciilt6rleefe1o7marhlssi4a5pnm8.png)
![AM=2* 0.62](https://img.qammunity.org/2020/formulas/physics/high-school/n6cjm0fntb59kp0z0dn9ehmi1grjx93yw8.png)
AM = 1.24 miles
So, he is 1.24 miles from his starting point. Hence, this is the required solution.