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Which value is equivalent to (7•3•2)^2 / (7•5) x (7^0)^3 / 5^-3 x 5^-9 A. 6/25 B. 36/25 C. 12/5 D. 252/5
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3 votes
Which value is equivalent to

(7•3•2)^2 / (7•5) x (7^0)^3 / 5^-3 x 5^-9

A. 6/25
B. 36/25
C. 12/5
D. 252/5

User Trilla
by
7.7k points

1 Answer

0 votes

Answer:

No one.

Explanation:


\frac{(7^0)^3}{[tex]\\\frac{((7*3*2)^2)/((7*5)(7^0)^3)}{5^(-3) *5^ {-9}} = ((7^2*3^2*2^2)/((7*5)(1)))/(5^(-12)) =((7*3^2*2^2)/(5))/(5^(-12)) =(7*3^2*2^2)/(5^(-11))= 7*3^2*2^2*{5^(11)}=1.23* 10^(10)} = \frac{1}{5^ {-12}} = 5^ {12}[/tex]

User Sean Stopnik
by
7.4k points
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