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A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in^2, what is the ratio of the circumference of the circumscribed circle to the one of the inscribed?

User Cyntech
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1 Answer

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The area of the square is 9 in^2

The side of a square is the square root of the area.

Side of square = √9 = 3 inches.

The side of the square is the diameter of the inscribed circle.

Circumference of a circle is PI x diameter.

Circumference of inscribed circle = 3.14 x 3 = 9.42 inches

The diameter for the circumscribed circle would be the diagonal of the square which is 3√2 = ( Side length x √2) ≈ 4.2426

The circumference = 3.14 x 3√2 = 13.321

Find the ratio between the two circles:

Circumscribed / inscribed =

13.321 / 9.42 = 1.41

User Tahoar
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