Question

Use the quadratic formula to solve the equation 4x^2+6x-4=0

Answer 1

`\large\boxed{x=-2\ or\ x=(1)/(2)}`

Explanation:

`\text{The quadratic formula of an equation}\ ax^2+bx+c=0\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\\text{We have}\ 4x^2+6x-4=0\to a=4,\ b=6,\ c=-4.\\\\\text{Substitute:}\\\\x=(-6\pm√(6^2-4(4)(-4)))/(2(4))=(-6\pm√(36+64))/(8)=(-6\pm√(100))/(8)\\\\x=(-6-10)/(8)=(-16)/(8)=-2\ or\ x=(-6+10)/(8)=(4)/(8)=(1)/(2)`