Question

If h(x) = 5 + x and k(X) =. 1/x which expression is equivalent to (kon)(x)?

Answer 1

For this case we have the following functions:

`h (x) = 5 + x\\k (x) = \frac {1} {x}`

We must find
`(k_ {0} h) (x)`:

By definition of compound functions we have to:

`(k_ {0} h) (x) = k (h (x)`

So:

`k (h (x) = \frac {1} {5 + x}`

Finally:

`(k_ {0} h) (x) = \frac {1} {5 + x}`

Answer:

`(k_ {0} h) (x) = \frac {1} {5 + x}`

Answer 2

(5+x)/x

Explanation:

Given

h(x)= 5+x

k(x)= 1/x

(koh)(x)=?

Here you multiply

1/x( 5+x)

5/x +x/x

5/x+1 or

5/x +x/x

(5+x)/x