Question

Tan A+ Tan (90-A) = secA .sec (90-A)​

Answer 1

see explanation

Explanation:

Using the cofunction identities

tan(90 - A) = cotA and cscA = sec(90- A)

Consider the left side

tanA + tan(90 - A)

= tanA + cotA

=
`(sinA)/(cosA)` +
`(cosA)/(sinA)`

=
`(sin^2A+cos^2A)/(cosAsinA)`

=
`(1)/(cosAsinA)`

=
`(1)/(cosA)` ×
`(1)/(sinA)`

= secA × cscA

= secA. sec(90 - A) = right side ⇒ verified