Tan A+ Tan (90-A) = secA .sec (90-A)

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Marius B · Answer 1 · 2020-06-27T08:41:29+0000

Answer:

see explanation

Explanation:

Using the cofunction identities

tan(90 - A) = cotA and cscA = sec(90- A)

Consider the left side

tanA + tan(90 - A)

= tanA + cotA

=
(sinA)/(cosA) +
(cosA)/(sinA)

=
(sin^2A+cos^2A)/(cosAsinA)

=
(1)/(cosAsinA)

=
(1)/(cosA) ×
(1)/(sinA)

= secA × cscA

= secA. sec(90 - A) = right side ⇒ verified

Tan A+ Tan (90-A) = secA .sec (90-A)

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Tan A+ Tan (90-A) = secA .sec (90-A)​

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Tan A+ Tan (90-A) = secA .sec (90-A)