Question

Find the value of x (6x-10) (6x+10)
15
26
46
80

Answer 1

total there are 3 values of x as +5/3, -5/3 and 0

Explanation:

the given equation is

x(6x-10) (6x+10)=0

this equation can be solved as following

`x(36x^2-100)` =0 using the formula (a+b)*(a-b)= (a^2-b^2)

here a=6x and b=10

from here we can write either x=0 or 36x^2= 100

or x^2= 100/36 and x=0

or x= ±10/6 and x=0

therefore, total there are 3 values of x as +5/3, -5/3 and 0

Answer 2

No one is the value

Explanation:

x(6x-10)(6x+10)=0

x(6x-10)(6x+10)=x(36x^2 - 100)= 0. This can be if and only if

x=0 or 36x^2 - 10^2=0 → 36x^2=100 → x^2=25/9 →

`x=√(25/9) =5/3= 1.7 =2`