How many solutions does 4(x-1)=4x+5

Question

asked Jan 27, 2020 155k views

2 Answers

AKHolland · Answer 1 · 2020-01-29T21:06:15+0000

4(x - 1) = 4x + 5

Eliminate parentheses on the left:

4x - 4 = 4x + 5

Subtract 4x from each side:

-4 = +5

No value of x can make this a true statement. So no solution exists.

George Asda · Answer 2 · 2020-02-01T13:53:56+0000

Answer:

NO SOLUTION

Explanation:

To solve this problem, first you have to isolate it on one side of the equation.

First, expand.

$\displaystyle 4(x-1)=4x-4$

$\displaystyle 4x-4=4x+5$

Next, add 4 from both sides.

$\displaystyle 4x-4+4=4x+5+4$

Solve.

$\displaystyle 4+5=9$

$\displaystyle 4x=4x+9$

Subtract 4x from both sides.

$\displaystyle 4x-4x=4x+9-4x$

Solve.

$\displaystyle 0=9$

Therefore, there are no solution.