Question

Calculate the value of [CH3OH][CO][H2]2 when all concentrations are 2.4. Keep in mind that the reaction may not be at equilibrium under these conditions.

Answer 1

Step-by-step explanation:

The given reaction will be as follows.

`CO + 2H_(2) \leftrightharpoons CH_(3)OH`

So, equilibrium constant for this equation will be as follows.

`K_(c) = ([CH_(3)OH])/([CO][H_(2)]^(2))`

As it is given that concentration of all the species is 2.4. Therefore, calculate the value of equilibrium constant as follows.

`K_(c) = ([CH_(3)OH])/([CO][H_(2)]^(2))`

=
`(2.4)/(2.4 * (2.4)^(2))`

= 0.173

Thus, we can conclude that equilibrium constant for the given reaction is 0.173.