Answer:
The required equation is h(t)= -(x - 6)² + 64.
Explanation:
Consider the provided information.
The vertex form of a parabola is:
f(x) = a(x - h)² + k, where (h, k) is the vertex of the parabola.
The projectile reaches a maximum height of 64 meters after 6 seconds, According to the laws of physics on his planet, the height of the projectile, h, after t seconds is modeled by a quadratic equation.
The quadratic equation has maximum height h = 64 after t = 6 second.
Thus, the vertex of the parabola is (6,64)
Use the above vertex form to find the equation of parabola.
f(x) = a(x - 6)² + 64
It is given that after 14 seconds, the projectile has a height of 0 meters.
Thus, the second point is (14,0)
Now to find the value of "a", Substitute the values of the second point in above equation and solve for "a".
0 = a(14 - 6)² + 64
0 = a(8)² + 64
0 = 64a + 64
-64 = 64a
a = -1
Hence, the required equation is h(t)= -(x - 6)² + 64.