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Eric made a scale drawing of the middle school. The scale he used was 1inch=5feet. If the gym is 30 inches by 20 inches in the drawing, what is the acual length and width of the gym.

2 Answers

9 votes

Answer:

Answer: 150 feet : 100 feet

Explanation:

From the question, we are informed that the scale used by Eric was 1inch=5feet.

If the gym is 30 inches by 20 inches in the drawing, the actual length and width of the gym would be:

Length = 30 inches = 30 × 5 feet = 150 feet

Width = 20 inches = 20 × 5 feet = 100 feet

User Ramesh R
by
3.5k points
4 votes

Answer: 150 feet : 100 feet

Explanation:

From the question, we are informed that the scale used by Eric was 1inch=5feet.

If the gym is 30 inches by 20 inches in the drawing, the acual length and width of the gym would be:

Length = 30 inches = 30 × 5 feet = 150 feet

Width = 20 inches = 20 × 5 feet = 100 feet

Therefore, the acual length and width of the gym would be 150 feet by 100 feet

User Rpax
by
3.1k points