14.8k views
0 votes
What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K? The latent heat of vaporization of water is 2.25 x 10^6 J kg-1.

2 Answers

5 votes

Answer:

0.88

Step-by-step explanation:

User Bwalshy
by
6.8k points
4 votes

Answer : The mass of a sample of water is, 888.89 grams

Explanation :

Latent heat of vaporization : It is defined as the amount of heat energy released or absorbed when the liquid converted to vapor at atmospheric pressure at its boiling point.

Formula used :


q=L* m

where,

q = heat = 2000 kJ =
2* 10^6J (1 kJ = 1000 J)

L = latent heat of vaporization of water =
2.25* 10^6J/kg

m = mass of sample of water = ?

Now put all the given values in the above formula, we get:


2* 10^6J=(2.25* 10^6J/kg)* m


m=0.88889kg=888.89g (1 kg = 1000 g)

Therefore, the mass of a sample of water is, 888.89 grams

User Anton Norka
by
6.5k points